Question

mahajan has a vegetable garden in the shape of a rhombus . the lenght of each side of the garden is 35 m and its diagnol is 42m long . after growing the vegetables in it , he wants to divide it in six equal parts , find the area of each part

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Answer 1

Answer:

196m^2

Step-by-step explanation:

side = 35m(AB=BC=CD=AD)

diagonal = 42m(AC)

Diagonals in a rhombus bisect each other and are perpendicular to each other.

Let ABCD be a rhombus and AC and BD be it's diagonals and O be it's point of intersection.

Take any triangle from 4 triangle say Triangle AOD.

angle AOD = 90°

AO = 42m/2 = 21m

AD = 35m

By Pythagoras Theorem,

(AD)^2 = (AO)^2 + (DO)^2

(35m)^2 = (21m)^2 + (DO)^2

1225m^2 = 441m^2 + (DO)^2

1225m^2 - 441m^2 = (DO)^2

784m^2 = (DO)^2

√784m^2 = DO

28m = DO

BD = 2 × 28m = 56m

Area of rhombus = 1/2 × AC × BD

= 1/2 × 42m × 56m

= 1176m^2

Area of each part/ Area of 6 equal parts = 1176m^2/6 = 196m^2

PLEASE MARK MY ANSWER AS BRAINLIEST.

Answer 2

Step-by-step explanation:

Heya mate!...

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