Math, asked by smadhumithra04, 5 hours ago

mahalajsThe length of the rectangular field is 10 m more than that of the breadth and the

perimeter is 160 m.Find the area of the rectangle?

Answers

Answered by akkubawatkubawat
1

Answer:

area of rectangle is = 1575m²

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Answered by steffiaspinno
0

The area of the rectangle is 1575 m²

Explanation:

Given:

1. The length of the rectangular field is 10 m more than that of the breadth

2. The perimeter is 160 m.

Formula:

Area of the rectangle = l×b sq units

Perimeter of the rectangle = 2×(l+b)

Solution:

==> Perimeter = 160 m

==> Form the given Condition,

==> let, length be l and breadth be b.

==> Length = l

==> Breadth=b

==> length of the rectangular field is 10 m more than that of the breadth

==> l = 10+b

==> Substitute the l and b value in perimeter formula

==> P = 2(l+b)

==> P=160cm

==> 160 = 2((10+b)+b)

==> 160 = 2(10+2b)

==> 160÷2 = 10+2b

==> 80 = 10+2b

==> 2b = 80-10

==> 2b = 70

==> b = 70÷2

==> b = 35

==> l = 10+b

==> Substitute b value in the equation

==> l = 10+35

==> l=45

==> Area of the rectangle = l×b

==> Area = 35×45

==> Area = 1575 m²

The area of the rectangle is 1575 m²

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