Maharashtra konatya sultani barasa bhag vatun ghetlay hota Marathi standard 5th
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Let x = Distance between the boundaries of the lawn and the pond.
Length of pond =(50−2x) m and breadth of pond =(40−2x)m
Area of pond = Area of lawn − Area of grass around pond.
∴(40−2x)(50−2x)=(50)(40)−1184
2000−1184=2000−180x+4x²
⇒x²−45x+296=0
⇒x² −8x−37x+296=0
⇒x(x−8)−37(x−8)=0
⇒(x−8)(x−37)=0
x=37,x=8
If x=8,l=50−2x=34m
b=40−2x=24m
Taking x=8 as more realistic value, length of pond will be 34m and breadth will be 24m.
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Maharashtra konatya sultani barasa bhag vatun
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