Mahendra and virat are sitting at a distance of 1 meter form eachother. Their masses are 15 kg and 80 kg respectively. What is the gravitation force between them ? (G = 6.67x 10^-11 )
Answers
Answered by
13
Here is your answer:
Given: r=1m ,m1=75kg, m2=80kg.
According to Newton's law..
F= Gm1m2/r*r
F=6.67*10'-11*75*80/1*1
F=4.002*10'-7 N
The gravitational force between Mahendra and Virat is 4.002*10'-7 N.
Hope it will help...
Given: r=1m ,m1=75kg, m2=80kg.
According to Newton's law..
F= Gm1m2/r*r
F=6.67*10'-11*75*80/1*1
F=4.002*10'-7 N
The gravitational force between Mahendra and Virat is 4.002*10'-7 N.
Hope it will help...
anshkhatwani67:
helpful
Answered by
13
Answer:
Explanation:
Hope it helps
Attachments:
Similar questions