Mahendra and Virat are sitting at a distance of 1 metre from each other. Their masses are 75
kg and 80 kg respectively.
What is the gravitational force between them?
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Answer:
Given :-
Radius = 1 m
m₁ = 75 kg
m₂ = 80 kg
G = 6.67 × 10⁻¹¹ Nm²/kg²
To Find :-
Gravitational force between them.
Formula to be used :-
Newton's Law i.e F = Gm₁m₂/r²
Solution :-
Putting all the values,we get
F = Gm₁m₂/r²
F = 6.67 × 10⁻¹¹ × 75 × 80/1² n
F = 4.002 × 10⁻⁷ N
Hence, the gravitational force between Mahesh and virat 4.002 × 10⁻⁷ N.
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