mahendra and virat are sitting at a distance of 1 metre from each other.their masses are 75 kg and 80 kg respectively.what is the gravitational force between them?
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Answer: F=3.64mN or 0.00364N
Explanation:
F=Gm1m2/r²
G=(6.674×10^-11)m²/kg.s²
F=6.674×10^-11×75×80/1
F=3.64×10⁸×10^-11
F=3.64×10^-3N
Or F=3.64mN or 0.00364N
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