Question

Mahendra and Virat are sitting at a distance of one metre from each other. there masses are 75 kg and 80 kg respectively. what is rhe gravitational force berween them?​

Answer 1

GiveN :

• Mass of Mahendra $\sf{(M_m) = 75 kg}$
• Mass of Virat $\sf{(M_v) = 80 kg}$
• Distance between them $\sf{(r) = 1m}$

To FinD :

• Gravitational Force between them

SolutioN :

Gravity is a natural phenomenon, it is an attractive force on each any every object or body on each other. It is most accurately explained with $\tt{\green{Theory\ of\ Relativity}}$ given by the great mathematician and physicist $\sf{\red{Issac\ Newton}}$ , he is known as Father of modern Physics. Gravitational force is the weakest force which exists in nature .

As we know that :

$\LARGE{\boxed{\sf{g = G \dfrac{M_m M_v}{r^2}}}} \\ \\ \\ \implies \sf{g = G \dfrac{75 \times 80}{1^2}} \\ \\ \\ \implies \sf{g = 6.67 \times 10^{-11} \bigg( \dfrac{6000}{1} \bigg) } \\ \\ \\ \implies \sf{g = (6.67 \times 10^{-11}) \times (6 \times 10^3)} \\ \\ \\ \implies \sf{g = 40.02 \times 10^{-11 + 3}} \\ \\ \\ \implies \sf{g = 40.02 \times 10^{-8} ms^{-2}} \\ \\ \\ \underline{\rm{\therefore\ Gravitational\ force\ between\ them\ is\ 40.02\ \times\ 10^{-8} ms^{-2}}}$

Answer 2

Given :-

Radius = 1 m

m₁ = 75 kg

m₂ = 80 kg

G = 6.67 × 10⁻¹¹ Nm²/kg²

To Find :-

Gravitational force between them.

Formula to be used :-

Newton's Law i.e F = Gm₁m₂/r²

Solution :-

Putting all the values,we get

F = Gm₁m₂/r²

F = 6.67 × 10⁻¹¹ × 75 × 80/1² n

F = 4.002 × 10⁻⁷ N

Hence, the gravitational force between Mahesh and virat 4.002 × 10⁻⁷ N.