Question

Mahendra invests rs 1960 and rs 1850 at the same rate of interest and receives rs 11 more as interest in one case than in the other every year. What is the rate?

Answer 1

Given

Sum1 (p1) =₹1960

Sum2 (p2) =1850

Rate of interest same

Difference between interest =₹11

In every yr

Difference = interest on sum 1 - interest on sum 2

Interest =pxrxt /100

$difference = ( \frac{p1 \times r \times t}{100} ) - ( \frac{p2 \times r \times t}{100} )$

$11 = ( \frac{1960 \times r \times 1}{100} ) - ( \frac{1850 \times r \times 1}{100} )$


$11 = 19.6r - 18.5r$

11=1.1r

R=11/1.1

R=10%


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