Question

Mahesh and virat are sitting at a distance of 1 metre from each other.Their masses are 75kg and 80 kg. What is the gravitional force between them.

Answer 1

$\huge{\text{\underline{Question:-}}}$

Mahesh and virat are sitting at a distance of 1 metre from each other.Their masses are 75kg and 80 kg. What is the gravitional force between them.

$\huge{\text{\underline{Solution:-}}}$

★ Given:-

• r = 1 m
• m1 = 75 kg
• m2 = 80 kg

$\boxed{\tt{G = 6.67 × 10-^1{^1 Nm^2 / kg^2}}}$

★ Explaination:-

★ According to Newton's law:-

$\boxed{\tt{F = Gm_1 m_2 / r^2}}$

$\tt{F = 6.67 × 10 -^1{^1 × 75 × 80 / 1^2 N}}$

$\boxed{\tt{= 4.002 × 10-^7 N}}$

The gravitational force between Mahesh and Virat is $4.002 × 10-^7 N$

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Answer 2

Answer:

Explanation:

Given :-

Radius = 1 m

m₁ = 75 kg

m₂ = 80 kg

G = 6.67 × 10⁻¹¹ Nm²/kg²

To Find :-

Gravitational force between them.

Formula to be used :-

Newton's Law i.e F = Gm₁m₂/r²

Solution :-

Putting all the values,we get

F = Gm₁m₂/r²

F = 6.67 × 10⁻¹¹ × 75 × 80/1² n

F = 4.002 × 10⁻⁷ N

Hence, the gravitational force between Mahesh and virat 4.002 × 10⁻⁷ N.