Math, asked by anujbharti012, 4 months ago

Mahesh borrowed a certain sum for two years at simple interest from Bhim.
Mahesh lent this sum to Vishnu at the same rate for two years compound interest.
At the end of two years, Mahesh received Rs.410 as compound interest but paid
Rs.400 as simple interest. Find the sum and rate of interest.

Answers

Answered by thrinathk98
0

Answer:

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Answered by priyanka18885
2

Answer:

The sum borrowed by Mukesh=4000

Rate of Interest=5% p.a

Step-by-step explanation:

We know that SI = PRT/100

P = SI * 100/r*t

= 400 * 100 / r * 2

= 20000/R

We know that CI = P(1+r/100)^n - P

= P(1+r/100)^n - 1

410 = 20000/R(1+r/100)^n - 1

410 = 20000/R(10000 + R^2 + 2000R - 10000)/10000

410 = 2/R(R^2 + 200R)

410R = 2(R^2+200R)

2R^2 + 400R - 410R = 0

2R^2 = 10R

Rs =5

P = 20000/5

= 4000.

Sum = 4000, Rate =5%

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