Math, asked by rana1214, 7 days ago

Mahesh borrowed a certain sum of two years and the simple interest from Bhim Mahesh land this sum two Vishnu at the same rate for 42 years compound interest at the end of 2 years Mahesh received received rupees 410 at the compound interest but paid rupees 400 as simple interest find the sum and rate of interest​

Answers

Answered by VIBEKTIGGA
0

Answer:

5$

Step-by-step explanation:

We know that SI = PTR/100

P = SI * 100/r*t

= 400*100/r * 2

= 20000/R

- (1)

We know that CI = P(1+r/100)^n - P

= P(1+r/100)^n - 1

410 = 20000/R(1+r/100)^n - 1

410 = 20000/R(10000 + R^2 + 2000R-10000)/10000

410 = 2/R(R^2 + 200R)

410R = 2(R^2+200R)

2R^2 +400R - 410R = 0

2R^2 = 10R

R = 5.

PLZ MAKE ME AS THE BRANILIES

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