Math, asked by sibaranisahu123, 11 months ago

mahesh borrows a certain sum of money for 2 year at s.I. from bhim mahesh lent the sum to vishnu at same rate for 2 year compound interest. At the end of 2 year ,mahesh received rupee 410 as C.I. but paid rupee 400 as S. I. find the sum and rate interest ​

Answers

Answered by MrPõisoñ
6

Answer:

We know that SI = PTR/100

                        P = SI * 100/r*t

                           = 400 * 100 / r * 2

                           = 20000/R  ------------------ (1)

We know that CI = P(1+r/100)^n - P

 

                           = P(1+r/100)^n - 1

                    410 = 20000/R(1+r/100)^n - 1

                    410 = 20000/R(10000 + R^2 + 2000R - 10000)/10000

                    410 = 2/R(R^2 + 200R)

                    410R = 2(R^2+200R)

                    2R^2 + 400R - 410R = 0

                    2R^2 = 10R

                       R = 5.

Substitute R in (1), we get

P = 20000/5

  = 4000.

Sum = 4000, Rate of interest = 5%.

i hope this will help uhh !

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