Math, asked by smmandal8, 6 months ago

Mahesh bought a house for Rs 200,000. At the end of the first year, he sold it at a loss of 10% on
his investment. He invested the money, thus, obtained at 20% per annum compound interest for
2 years. The value of his investment would amount to (in Rs)
(B) 240,300
(D) 233,233
(A) 230,200
(C) 259,200​

Answers

Answered by rachitnkg
1

Answer:

(c) 259,200

Step-by-step explanation:

Solution :

Selling price of the house

<br> Sum invested in the second year =Rs. 180000 <br> This would amount to (in Rs. )=180000 <br>

<br> =259200.

Answered by rajasriv
0

Cost price(CP)=Rs.200,000

Loss percent(L%)=10%

Selling price(SP)=90% of 200,000

                          =90/100*200,000

                          =Rs.180,000

Principal(P)=Rs.1,80,000

Rate of interest(R)=20% per annum

Time period(n)=2 years

Amount(A)=P(1+R/100)^n

                 =180,000(1+20/100)^2

                 =180,000(6/5)^2

                 =180,000*36/25

                 =Rs.259,200

Therefore,

The value of his investment will amount to Rs.259,200

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