Question

mahesh invest rs3000 for 3 years at 10% p.a compound interest find the amount and the compound interest that Ramesh will get after 3 years​

Answer 1

Step-by-step explanation:

The answer is 993.

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Answer 2

$\begin{gathered}\begin{gathered} \frak{ \red{{Given}}} \begin{cases} \sf{ Principal = Rs.3000} \\ \sf{Rate = 10 \%} \\ \sf{Time = 3 years} \end{cases} \end{gathered}\end{gathered}$

$\begin{gathered} \frak{ \red{{To \: Find}}} \begin{cases} \sf{ The \: compound\: interest \: and \: amount} \end{cases} \end{gathered}$

$\large{ \frak{ \red{Solution :}}}$

$\sf Let's \: find \: the \: compound \: interest.$

$\tt\implies \boxed{ \green{{ \sf Amount = \tt P \left[ 1 + \dfrac{ R }{100} \right]^{n } }}}$

${ \sf{Here, \: \: \: \: }}{ \sf{P = 3000}} \\ { \sf{ \: \: \: \: \: \: \: \: \: R = 10}} \\ {\sf{ \: \: \: \: \: \: \: n= 3}}$

$\tt\implies { \sf Amount = \tt 3000 \left[ 1 + \dfrac{ 10 }{100} \right]^{3 } }$

$\tt\implies { \sf Amount = \tt 3000 \left[ \dfrac{100 + 10 }{100} \right]^{3 } }$

$\tt\implies { \sf Amount = \tt 3000 \left[ \dfrac{110}{100} \right]^{3 } }$

$\tt\implies { \sf Amount = \tt 3000 \left[ \dfrac{11}{10} \right]^{3 } }$

$\tt\implies { \sf Amount = \tt 3000 \left[ \dfrac{11}{10} \times \dfrac{11}{10} \times \dfrac{11}{10} \right] }$

$\tt\implies { \sf Amount = \tt 3 \cancel0 \cancel0 \cancel0 \left[ \dfrac{11 \times 11 \times 11}{1 \cancel0 \times 1 \cancel0 \times 1 \cancel0} \right]}$

$\tt\implies { \sf Amount = \tt 3 \left[ \dfrac{11 \times 11 \times 11}{1 \times 1 \times 1 } \right]}$$\tt\implies { \sf Amount = \tt 3 \left[ \dfrac{1331}{1 } \right]}$

$\tt\implies { \bf{Amount = \tt 3 \left[ 1331\right]}}$

$\sf{ \purple{The \: amount \: is \: Rs. 3993.}}$

$\sf{Compound \: Interest = Amount - Principal}$

$= 3993 - 3000$

$\bf= 993$

$\sf{ \purple{Therefore, the Compound \: Interest \: is \: Rs. \: 993.}}</p><p>$