Question

Mahesh invests Rs.3000 for 3 years at rate of 10th p. a. Compound interest.Find the amount and the compound interest that Makesh will get after 3 years.​

Answer 1

Answer:

Solution :

find the compound interest.

$\tt\implies \boxed{ \sf Amount = \tt P \left[ 1 + \dfrac{ R }{100} \right]^{n } }$

P = 3000

R = 10

N = 3

$\tt\implies { \sf Amount = \tt 3000 \left[ 1 + \dfrac{ 10 }{100} \right]^{3 } }$

$\tt\implies { \sf Amount = \tt 3000 \left[ \dfrac{100 + 10 }{100} \right]^{3 } }$

$\tt\implies { \sf Amount = \tt 3000 \left[ \dfrac{110}{100} \right]^{3 } }$

$\tt\implies { \sf Amount = \tt 3000 \left[ \dfrac{11}{10} \right]^{3 } }$

$\tt\implies { \sf Amount = \tt 3000 \left[ \dfrac{11}{10} \times \dfrac{11}{10} \times \dfrac{11}{10} \right] }$

$\tt\implies { \sf Amount = \tt 3000 \left[ \dfrac{11 \times 11 \times 11}{10 \times 10 \times 10} \right]}$

$\tt\implies { \sf Amount = \tt 3 \cancel0 \cancel0 \cancel0 \left[ \dfrac{11 \times 11 \times 11}{1 \cancel0 \times 1 \cancel0 \times 1 \cancel0} \right]}$

$\tt\implies { \sf Amount = \tt 3 \left[ \dfrac{11 \times 11 \times 11}{1 \times 1 \times 1 } \right]}$

$</p><p>\tt\implies { \sf Amount = \tt 3 \left[ \dfrac{1331}{1 } \right]}$

$\tt\implies { \sf Amount = \tt 3 \left[ 1331\right]}$

$\implies \tt Amount = 3 \times 1331$

$\implies \tt Amount = 3993$

Therefore, the Amount is Rs. 3993.

Compound Interest = Amount - Principal

= 3993 - 3000

= 993

Step-by-step explanation:

Hope it helps <(￣︶￣)>

Answer 2

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