Math, asked by ritik6725, 1 year ago

Mahesh is thrice as old as Tarun. two years ago, his age was four times of Tarun 's age. find their present ages.

Answers

Answered by abhi569
0
Let the age of tarun be ( x ) years
So, Age of mahesh will be ( 3x ) years



Two years ago, his age was four times of tarun's age

=> ( 3x - 2 ) = 4( x - 2 )

=> 3x - 2 = 4x - 8

=> -2 + 8 = 4x - 3x

=> 6 = x




Hence, age of tarun = x = 6 years
Age of mahesh = 3x = 3(6) = 18 years


.


Answered by Panzer786
4
Heya !!





Let present age of tarun be X years.




Present age of mahesh = 3X years.






Before two years age of tarun = ( X - 2 ) years.



Before two years age of mahesh = ( 3X - 2 ) years.



According to the question,





3X - 2 = 4 ( X - 2 )




3X - 2 = 4X - 8




4X - 3X = 8 - 2




X = 6 years




Present age of tarun = X = 6 years.




And,


Present age of mahesh = 3X = 3 × 6 = 18 years.
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