Math, asked by ritik6725, 1 year ago

Mahesh is thrice as old as Tarun. two years ago, his age was four times of Tarun age. find their present ages

Answers

Answered by Kirttish
4
Let Tarun's age be x.
Therefore, Mahesh's age =3x
A/Q, 3x - 2 = 4(x - 2)
=> 3x - 2 = 4x - 8
=> 3x - 4x = -8 + 2
=> -x = -6
=> x = 6
Therefore, Tarun's age is 6 and Mahesh's age is 18

HOPE YOU LIKE IT.

PLEASE GIVE BRANLIEST ANSWER IF YOU RECIVED WHAT YOU WANTED.
Answered by abhi569
1
Let the age of tarun be ( x ) years
So, Age of mahesh will be ( 3x ) years



Two years ago, his age was four times of tarun's age

=> ( 3x - 2 ) = 4( x - 2 )

=> 3x - 2 = 4x - 8

=> -2 + 8 = 4x - 3x

=> 6 = x



Hence, age of tarun = x = 6 years
Age of mahesh = 3x = 3(6) = 18 years
Similar questions