Mahesh is thrice as old as Tarun. two years ago, his age was four times of Tarun age. find their present ages
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Let Tarun's age be x.
Therefore, Mahesh's age =3x
A/Q, 3x - 2 = 4(x - 2)
=> 3x - 2 = 4x - 8
=> 3x - 4x = -8 + 2
=> -x = -6
=> x = 6
Therefore, Tarun's age is 6 and Mahesh's age is 18
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Therefore, Mahesh's age =3x
A/Q, 3x - 2 = 4(x - 2)
=> 3x - 2 = 4x - 8
=> 3x - 4x = -8 + 2
=> -x = -6
=> x = 6
Therefore, Tarun's age is 6 and Mahesh's age is 18
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PLEASE GIVE BRANLIEST ANSWER IF YOU RECIVED WHAT YOU WANTED.
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Let the age of tarun be ( x ) years
So, Age of mahesh will be ( 3x ) years
Two years ago, his age was four times of tarun's age
=> ( 3x - 2 ) = 4( x - 2 )
=> 3x - 2 = 4x - 8
=> -2 + 8 = 4x - 3x
=> 6 = x
Hence, age of tarun = x = 6 years
Age of mahesh = 3x = 3(6) = 18 years
So, Age of mahesh will be ( 3x ) years
Two years ago, his age was four times of tarun's age
=> ( 3x - 2 ) = 4( x - 2 )
=> 3x - 2 = 4x - 8
=> -2 + 8 = 4x - 3x
=> 6 = x
Hence, age of tarun = x = 6 years
Age of mahesh = 3x = 3(6) = 18 years
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