mahima covers one seventh of her journey on monday. she covers three fourth her journey on tuesday. (how much portion of journey is left for the completion?)
Answers
Given :- mahima covers one seventh of her journey on monday. she covers three fourth her journey on tuesday. (how much portion of journey is left for the completion ?
Solution :-
Let us assume that, total length of the journey is x km .
so,
→ Distance covered by mahima on monday = (1/7) of x = (x/7) km
and,
→ Distance covered by mahima on tuesday = (3/4) of x = (3x/4) km
then,
→ Total distance covered by mahima in two days = (x/7) + (3x/4) = (x * 4 + 3x * 7)/28 = (4x + 21x)/28 = (25x/28) km
therefore,
→ Distance left to be covered = x - (25x/28) = (3x/28) km
hence,
→ Portion of journey left = (3x/28) / x = (3/28) (Ans.)
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Given : Mahima covers one seventh of her journey on Monday.
She covers three fourth of journey on Tuesday.
To Find : how much portion of journey is left for the completion
Solution:
Assume that Total Journey = 28D
Mahima covers one seventh of her journey on Monday.
Hence covered on Monday = ( 1/7) 28D = 4D
three fourth of journey on Tuesday.
Hence covered on Tuesday = (3/4) 28D = 21D
Covered total = 4D + 21D = 25D
Left = 28D - 25D = 3D
portion of journey is left for the completion = 3D/28D = 3/28
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