Math, asked by adi1462007, 15 days ago

mahima covers one seventh of her journey on monday. she covers three fourth her journey on tuesday. (how much portion of journey is left for the completion?)​

Answers

Answered by RvChaudharY50
1

Given :- mahima covers one seventh of her journey on monday. she covers three fourth her journey on tuesday. (how much portion of journey is left for the completion ?

Solution :-

Let us assume that, total length of the journey is x km .

so,

→ Distance covered by mahima on monday = (1/7) of x = (x/7) km

and,

→ Distance covered by mahima on tuesday = (3/4) of x = (3x/4) km

then,

→ Total distance covered by mahima in two days = (x/7) + (3x/4) = (x * 4 + 3x * 7)/28 = (4x + 21x)/28 = (25x/28) km

therefore,

→ Distance left to be covered = x - (25x/28) = (3x/28) km

hence,

→ Portion of journey left = (3x/28) / x = (3/28) (Ans.)

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Answered by amitnrw
0

Given :  Mahima covers one seventh of her journey on Monday.

She covers three fourth of journey on Tuesday.

To Find : how much portion of journey is left for the completion

Solution:

Assume that Total Journey  = 28D

Mahima covers one seventh of her journey on Monday.  

Hence covered on Monday  = ( 1/7) 28D  = 4D

three fourth of journey on Tuesday.

Hence covered on Tuesday  = (3/4) 28D  = 21D

Covered  total = 4D + 21D = 25D

Left = 28D - 25D  = 3D

portion of journey is left for the completion  = 3D/28D  = 3/28

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