Math, asked by adi1462007, 7 hours ago

mahima covers one seventh of her journey on monday. she covers three fourth her journey on tuesday. (how much portion of journey is left for the completion?)​

Answers

Answered by RvChaudharY50
1

Given :- mahima covers one seventh of her journey on monday. she covers three fourth her journey on tuesday. (how much portion of journey is left for the completion ?

Solution :-

Let us assume that, total length of the journey is x km .

so,

→ Distance covered by mahima on monday = (1/7) of x = (x/7) km

and,

→ Distance covered by mahima on tuesday = (3/4) of x = (3x/4) km

then,

→ Total distance covered by mahima in two days = (x/7) + (3x/4) = (x * 4 + 3x * 7)/28 = (4x + 21x)/28 = (25x/28) km

therefore,

→ Distance left to be covered = x - (25x/28) = (3x/28) km

hence,

→ Portion of journey left = (3x/28) / x = (3/28) (Ans.)

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Answered by amitnrw
0

Given :  Mahima covers one seventh of her journey on Monday.

She covers three fourth of journey on Tuesday.

To Find : how much portion of journey is left for the completion

Solution:

Assume that Total Journey  = 28D

Mahima covers one seventh of her journey on Monday.  

Hence covered on Monday  = ( 1/7) 28D  = 4D

three fourth of journey on Tuesday.

Hence covered on Tuesday  = (3/4) 28D  = 21D

Covered  total = 4D + 21D = 25D

Left = 28D - 25D  = 3D

portion of journey is left for the completion  = 3D/28D  = 3/28

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