Question

Mahima is trying to increase her fitness through exercise. The first day she walks 1500 metres and every day after that she increases this distance by 110 metres. How far will she be walking on the 12th day? Show your calculations using the formula for Tn of an arithmetic sequence

Answer 1

Arithmetic Sequence.

We can form an arithmetic sequence, whose

• first term, a = 1500
• common difference, d = 110

To find: How far will she be walking on the 12th day?

Solution: We know that, nth term of an arithmetic sequence is given by

tn = a + (n - 1)d

Using this formula, we get

t12 = 1500 + (12 - 1) * 110

= 1500 + 11 * 110

= 1500 + 1210

= 2710

Therefore Mahima will be walking a distance of 2710 metres on the 12th day.

Answer 2

Mahima walks a distance of 2710 metres on 12th day.

Given:

First day she walks = a = 1500 metres

After that the distance increased by her = d = 110 metres

Step-by-step explanation:

The Tn of an arithmetic sequence is given by the formula:

Tn = a + (n - 1)d

Where,

n = number of days = 12

On substituting the values, we get,

Tn = 1500 + ((12 - 1) × 110)

Tn = 1500 + (11 × 110)

Tn = 1500 + 1210

∴ Tn = 2710