Question

Mahima ordered 4 pairs of Blue bangles and some additional pairs of Green bangles. The price of the Blue
bangles per pair was twice that of the Green bangles. When the order was filled, it was found that the
number of pairs of the two colours had been interchanged. This increased the bill by 50%. The ratio of the
number of pairs of Blue bangles to the number of pairs of Green bangles in the original order was​

Answer 1

Answer:

The price of the black socks per pair be Rs.2y

⇒  The original bill =(4×2y+x×y)=8y+xy

⇒  The new bill after interchanged =(4×y+x×2y)=4y+2xy

The new bill is 50% more than the original bill.

∴  (8y+xy)+(8y+xy)×10050=4y+2xy

⇒  (8y+xy)+2(8y+xy)=4y+2xy

⇒  23×(8y+xy)=4y+2xy

⇒  23(8+x)=4+2x               [ Dividing both sides by y ]

⇒  3(8+x)=2(4+2x)

⇒  24+3x=8+4x

⇒  4x−3x=24−8

⇒  x=16

∴  The number of blue socks in the original bill are 16

⇒  The required ratio =164=4

Answer 2

Given :- Mahima ordered 4 pairs of Blue bangles and some additional pairs of Green bangles. The price of the Blue bangles per pair was twice that of the Green bangles. When the order was filled, it was found that the number of pairs of the two colours had been interchanged. This increased the bill by 50%. The ratio of the number of pairs of Blue bangles to the number of pairs of Green bangles in the original order was ?

Solution :-

Let us assume that, she ordered x pairs of green bangles.

also,

Let us assume that, the Price of green bangles is Rs.y / pair.

then,

→ Price of blue bangles = 2 * y = Rs.2y / pair.

so,

→ Total Price of 4 pairs of blue bangles ans x pair of green bangles = 4 * 2y + x * y = Rs.(8y + xy)

now, when number of pairs interchanged , we have, 4 pairs of green bangles ans x pair of blue bangles .

so,

→ New Price = x * 2y + 4 * y = Rs.(2xy + 4y)

A/q,

→ New Price = 150% of original Price

→ (2xy + 4y) = (150/100) * (8y + xy)

→ (2xy + 4y) = (3/2)(8y + xy)

→ 2(2xy + 4y) = 3(8y + xy)

→ 4xy + 8y = 24y + 3xy

→ 4xy - 3xy = 24y - 8y

→ xy = 16y

→ x = 16.

hence,

→ The ratio of the number of pairs of Blue bangles to the number of pairs of Green bangles in the original order was = 4 : 16 = 1 : 4 . (Ans.)

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