Question

Mahima, Ridhima and Hima are three sisters whose ages are in the ratio 7: 3: 5. If the sum of their ages is 225, then find the age of youngest sister. Answer the following questions.
If x is the common factor of their ages then the ages of sisters are: *​

Answer 1

Step-by-step explanation:

let age of mahima be 7x

let age of Ridhima be 3x

let age of hima be 5x

Now,

7x+3x+5x=225

15x=225

x=225/15

x=15

Age of Mahima 7x=7*15= 105yrs

Age of Ridhima=3x=3*15= 45yrs

Age of Hima= 5x= 5*15= 75yrs

Ridhima is the youngest sister among 3 of them and her age is 45 yrs

Answer 2

age of ridhima is=45

age of mahima =105

age of hima =75

Step-by-step explanation:

Method 1

sum of ratio =7+3+5=15

age of ridhima is=3/15*225=45

age of mahima =7/15*225=105

age of hima =5/15*225 =75

Method 2

5x +7x+3x =225

15x=225

x=15

age of ridhima is= 3x=45

age of mahima =7x =105

age of hima=5x =75