Question

Mahindra and virat are sitting at a distance of 1 meter from each other their masses are75kg and80 kg respectively whqt is the gravitational force between them ?G=6.67×10^-11Nm*2/kg*2​

Answer 1

$\\ \\ F = \frac {GM_{1}m_{2}}{{d}^{2}} \\ \\ F = \frac {6.67 \times {10}^{-11} \times 75 \times 80}{{1}^{2}} \\ \\ F = 40020 \times {10}^{-11} \: N$