Question

Mahindra area and perimeter of rectangle whose length and breadth are 14 cm and 10cm respectively​

Answer 1

Step-by-step explanation:

AREA=L ❌ B

=14×10=140 SQUARE CENTIMETRES

PERIMETER= 2(L+B)

• =2(14+10)=2×24=48 cm

Answer 2

$\mathfrak{ \large{\blue{ \underline{ \purple{ Given: }}}}}$

• Length of rectangle = 14 cm
• Breadth of rectangle = 10 cm

$\mathfrak{ \large{\blue{ \underline{ \purple{ To \: Find: }}}}}$

• Area and perimeter of rectangle

$\mathfrak{ \large{\blue{ \underline{ \purple{ Solution: }}}}}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \mathfrak{ \underline{ \green{Formula \: to \: calculate \: the \: area \: of \: rectangle}}}$

$\boxed{ \mathfrak{ \large{ \red{ \star \: \: \: \: \: \: { \large{ area = length \times breadth}}}}}}$

According to question,

$\large{ \sf \longmapsto \: \: \: \: \: \: \: \: \: area = 14 \times 10}$

$\large{ \sf \longmapsto \: \: \: \: \: \: \: \: area = \boxed { \mathfrak{ \orange{140 \: {cm}^{2} }}}}$

$\:\:\:\:\:\:\:\:\:\:\:\: \mathfrak{ \underline{ \green{Formula \: to \: calculate \: the \: perimeter \: of \: rectangle}}}$

$\boxed{ \mathfrak{ \star{ \large{ \red{ \: \: \: \: \: perimeter = 2(length + breadth)}}}}}$

According to question,

$\large{ \rm \longmapsto \: \: \: \: \: \: \: perimeter = 2(14 + 10)}$

$\large{\rm \longmapsto \: \: \: \: \: \: \: \: perimeter = 2 \times 24}$

$\large{ \rm \longmapsto \: \: \: \: \: \: \: perimeter = \boxed{ \orange{ \mathfrak{48 \: cm}}}}$

$\mathfrak{ \large{\blue{ \underline{ \purple{ Hence:}}}}}$

The area and perimeter of rectangle are 140 cm² and 48 cm.