Question

Main prithvi ladkiyan prashn apna paath yad karti Hain

Answer 1

The sample space has 6 possible outcomes-

S={1,2,3,4,5,6}.

Let all outcomes are equally likely(fair dice).

Hence Probability of any one outcome occurring= 1/6.

The event that we get that an even number on tossing the die can occur in 3 possible ways.

Let E denote this event.

E={2,4,6}

Now P(E)= 3×1/6=1/3

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Tusen Takk✌️❣️

Answer 2

Dette er ikke svaret ditt☹️

•°.•°.•°.•°.•°.•°.•°.•°.•°.•°.•°.•°.•°.•°.•°.•°.•°.•°.•°

✌️❣️

Let the height of the tree be y and width of the river be x and CD = 40 m

In ΔABD, tan 300 =

A

x

+

40

⇒ x+40 = y

√

3

………..(i)

In ΔABC,

tan 600 =

A

=

y

x

⇒ y = x

√

3

……………(ii)

Putting the value of y from (ii) to (i)

x+40= [x

√

3

]

√

3

= 3x

40 = 2x

⇒ x= 20

y = x

√

3

= 20

√

3

Height of the tree = 20

√

3

m

Width of the river = 20 m.

✌️❣️