Mainu requires 33% to pass if she gets 155 marks and fall short by 10 marks what are the maximum marks
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Pass marks=165 (15+10)
Pass percentage 33%
let x be the maximum marks
33%x=165
33x/100=165
x=16500/33
x=500
Maximum marks is 500
Pass percentage 33%
let x be the maximum marks
33%x=165
33x/100=165
x=16500/33
x=500
Maximum marks is 500
Answered by
3
Let, the maximum marks= Z
Percentage of marks required to pass=33%of a
Marks got by Mainu=155
Shortage of marks=10
Therefore passing mark=155+10=165
A.T.Q,
33% of Z=165
=>33/100 x Z=165
=>Z = 165 x 100/33=5 x 100=500
Therefore, maximum marks=500
Plz mark me BRAINIEST if you like my answer.
Percentage of marks required to pass=33%of a
Marks got by Mainu=155
Shortage of marks=10
Therefore passing mark=155+10=165
A.T.Q,
33% of Z=165
=>33/100 x Z=165
=>Z = 165 x 100/33=5 x 100=500
Therefore, maximum marks=500
Plz mark me BRAINIEST if you like my answer.
RSDebashisSaha:
plz mark me BRAINIEST
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