Question

MAIS CH4 + 202 Combustion CO2 + 2H20 at STP. Number of moles of CH4 and O2 used in combustion reaction of 22.4L of CH4 with 128 g of O2 is :-​

Answer 1

Answer:

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Answer 2

CH₄ + 2O₂ combustion CO₂ + 2H₂O at STP.

We have to find the no of moles of CH₄ and O₂ used in combustion reaction of 22.4L of CH₄ with 128 g of O₂.

What is combustion reaction ?

The reaction in which a chemical compound is burnt in the presence of adequate amount of oxygen is known as combustion of that compound.

        hydrocarbon produces carbon dioxide and water when it burns in the sufficient amount of oxygen.

mass of O₂ = 128g

molecular mass of O₂ = 32g/mol

no of moles of O₂ = mass of O₂/molecular mass of O₂

= 128/32 = 4 mol

volume of CH₄ = 22.4 L

no of moles of CH₄ = volume of CH₄/22.4 L = 22.4/22.4 = 1 mol

from the reaction, CH₄ + 2O₂ => 2H₂O + CO₂ , it is clear that one mole of methane reacts with two moles of oxygen.

so, the no of moles of used O₂ = 4 - 2 = 2 moles

the no of moles of used CH₄ = 1 [ completely used ]