Question

Make 16y²-40y+25 as a perfect square.​

Answer 1

Step-by-step explanation:

16y²-40y+25

(4y)^2-2×4×5+(5)^2

4y-5

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Answer 2

Answer:

$16 {y}^{2} - 40y + 25$

$= {(4y)}^{2} + (2)(4y)( - 5) + {5}^{2}$

${(4y - 5)}^{2}$

Hope this helps.

Hope this helps. Thanks.