Question

Make 3 different 3 digit numbers using 1,9and 8,where each digit can be used only once.check which of these numbers are divisible by 9​

Answer 1

The three different numbers are-

• 198
• 189
• 918

The sum of the digits is 1+9+8=18

which is divisible by 9

Therefore,

All the possible combination from the following digits will be divisible by 9

Hope you will understand...Thank You...

Answer 2

Answer:

198, 918, 891

Step-by-step explanation:

the three numbers are

198

918

891

198 is divisible by 9

918 is divisible by 9

891 is divisible by 9 also