Question

Make a frequency distribution table for the following data.

Mihira has a folder on her laptop with her photographs, from 1-5 years of age. She wants to organise those pictures into separate folders as per her age.
Here is a data of 20 photographs giving the age at which a photograph was taken:
2, 2, 3, 1, 1, 1, 4, 2, 3 , 5, 1, 1, 1, 1, 5, 2, 5, 2, 1, 1
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Answer 1

Step-by-step explanation:

$\sf \: Solution \:$

Let us now consider the number of photographs, between ages 1 and 21 years.

2, 2, 3, 1, 1, 1, 4, 8, 10, 2, 3, 5, 1, 1, 1, 1, 5, 2, 6 , 7, 6, 7, 5, 9, 2, 10, 1, 1, 8, 9, 10, 12, 13, 10, 11 , 10, 14, 18, 15, 12, 13, 15, 20, 17, 18, 21, 13, 13 , 20, 18, 16, 17, 15, 19, 12, 14, 21, 13, 18, 19

We know that the range of this data can be calculated as:

Range = Highest value - Lowest value

= 21 - 1 = 20

To find the highest and the lowest value of observation in a data we arrange the data in ascending or descending order. Such an arrangement of data is called an array.

We will now try to group the ages together to reduce the number of values in the data.

The smaller groups into which the values are divided are called class intervals or just class. The number of class intervals should not be too many or too few.

Take the first class interval as 0 - 5 .

In the class interval 0-5, 0 is called the lower class limit and 5 is called the upper class limit The size of each class interval is called the class width or class size.

The class size of class interval 0-5 is 5 - 0 = 5

Class size = Upper class size - Lower class size

Now we will make groups of class intervals each of range 5 starting from 0.

We will get the following class intervals:

0-5, 5-10, 10-15, 15-20, and 20-25.

Note that, the class size of each of these intervals is 5.

Answer 2

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