make a magic square with 4 to 12 with sum of 21 of row coloum and diagonal
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I think Question is wrong. The sum would be 24 otherwise
(i) Numbers are 2, 3, 4, 5, 6, 7, 8, 9 and 10, Sum = 18
(ii) Numbers are 3 to 11 and sum = 21
(iii) Numbers are 4 to 12 and sum = 24
(iv) Numbers are 6 to 14 and sum = 30
(v) Numbers are 7 to 15 and sum = 33
(vi) Numbers are 8 to 16 and sum = 36
(vii) Numbers are 9 to 17 and sum = 39
(i) Numbers are 2, 3, 4, 5, 6, 7, 8, 9 and 10, Sum = 18
(ii) Numbers are 3 to 11 and sum = 21
(iii) Numbers are 4 to 12 and sum = 24
(iv) Numbers are 6 to 14 and sum = 30
(v) Numbers are 7 to 15 and sum = 33
(vi) Numbers are 8 to 16 and sum = 36
(vii) Numbers are 9 to 17 and sum = 39
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