make a question for this identity (x+a)(x+b)=x²+(a+b)x+(a)(b)
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[ 5+1 ] [5+2]
[5 + 1] [5 + 2] = 5² + [1 + 2] 5 + [1×2]
[by using identity (x+a)(x+b)=x²+(a+b)x+(a)(b)]
[5 + 1] [5 + 2] = 25 + 3 × 5 + 2
= 25 + 15 + 2
= 40 + 2
= 42
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