Make a rule: Express the relationship and as an equation.
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Consider an object placed in front of a concave lens of focal length " f " on the principle axis of the lens. Concave lens forms a virtual and erect image at a distance of " q " from the optical centre of the lens as shown in the diagram below.
consider similar triangles ΔCO'P and ΔII'P
II
′
OO
′
=
II
′
P
O
′
P
II
′
OO
′
=
q
p
...................( 1 )
similarly in similar triangle ΔEFP and ΔII'F
II
′
EP
=
I
′
F
PF
II
′
OO
′
=
PF−PI
′
PF
II
′
OO
′
−
f−q
f
........................( 2 )
equation ( 1 ) and ( 2 )
q
p
−
f−q
f
p ( f - q ) = fq
pf - pq = fq
Dividing both sides by "pqf"
q
1
−
f
1
=
p
1
−
q
1
+
f
1
=
p
1
For a concave lens:
f
1
−
p
1
+
q
1
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