Question

Make a table to show the oxidizing agent, reducing agent, substance oxidized, substance reduced in the following equation:
1) Zn + CuSO4 ZnSO4 + Cu
2) 4NH3 + 5O2 4NO + 6H2O
3) SO2 + 2H2S 2H2O + S
Can I get an answer to this question ASAP?

Answer 1

Answer:

WHERE IS THE REACTANT AND THE PRODUCT FORMED IN THE REACTION???

PLEASE WRITE A CORRECT QUESTION....

Explanation:

Answer 2

Answer:

Zn + CuSO4 ---> ZnSO4 + Cu

Copper sulphate is the oxidizing agent as it gives oxygen to zinc and zinc is reducing agent as it accepts oxygen.

4NH3 + 5O2------> 4NO + 6H2O

The substance getting oxidised- NH3.

The substance getting reduced- O2.

The oxidising agent- O2.

The reducing agent - NH3.

SO2 + 2H2S-----> 2H2O + S

Sulfide has been oxidized, and sulfur dioxide is the oxidizing agent.

SO2 is being reduced to S . Here the substance being reduced is Sulphur dioxide (SO2).

H2S is changing into S. This is the removal of hydrogen from H2S. The removal of hydrogen is called oxidation. Thus H2S is be oxidised to S. Here the substance be oxidised is hydrogen sulphide (H2S).