make an imaginary calaculation to built a room of 3.5 mtr width and 4.7 mtr length with small tiles of 24c.m.s . answer intellectually including all the facilities
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no of tiles = area of room/area of tiles
= (3.5*4.7)/0.24*0.24
= 285.59. .....
so the no of tiles will be 286
= (3.5*4.7)/0.24*0.24
= 285.59. .....
so the no of tiles will be 286
aysha6:
plxzzzz
frst divide the area of floor by area of tile
then round up the answer to the next larger number
which is to be divided
dont think iam a disturbence
i dont know
pllzlzlzlzlzllzl
helloo
hooo
plz tell
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