Question

Make b the subject.

a=√b+6

Answer 1

Step-by-step explanation:

Can't Understand your question.

Assuming that,

Assuming that, Case I:

$a = \sqrt{b + 6} \\ on \: squaring \: both \: sides \\ = > {a}^{2} = ( { \sqrt{b + 6} })^{2} \\ = > {a}^{2} = b + 6 \\ = > {a}^{2} - 6 = b$

Case II:

$a = \sqrt{b} + 6 \\ = > a - 6 = \sqrt{b} \\ on \: squaring \: both \: sides \\ = > ( {a - 6})^{2} = ( { \sqrt{b} })^{2} \\ = > b = {a}^{2} - 12a + 36$

You can choose answer as per your question

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