Make b the subject of the formula : a = (1 + b^2)/(1 - b^2). Hence, find b, when a = 1.
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Answered by
0
a = 1-b^4
![b = \sqrt[4]{1 - a} b = \sqrt[4]{1 - a}](https://tex.z-dn.net/?f=b+%3D++%5Csqrt%5B4%5D%7B1+-+a%7D+)
when a =1
b =0
when a =1
b =0
Answered by
1
when a=1
1=1+b^2/1-b^2
1-b^2=1+b^2
2b^2=0
b=0
is your answer
1=1+b^2/1-b^2
1-b^2=1+b^2
2b^2=0
b=0
is your answer
shpriyanshu:
thank y so much
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