Question

make it in the form of a+bi ​

Answer 1

ANSWER✨✨✨✨✨

$\frac{4i {}^{8} - 3i {}^{9} + 3 }{3i {}^{11} - 4i {}^{10} - 2 } \\ = \frac{i {}^{8}(4 - 3i) + 3 }{i {}^{10}(3i - 4) - 2 } \\ = \frac{(4 - 3i) + 3}{i {}^{2}(3i - 4) - 2 } \\ = \frac{7 - 3i}{2 - 3i} \\ = \frac{(7 - 3i)(2 + 3i)}{(2 + 3i)(2 - 3i)} = \frac{(14 + 15i + 9)}{4 + 9} \\ = \frac{23 + 15i}{13} \\ = \frac{23}{13} + \frac{15}{13} i$

Answer 2

Answer:

$4 {i}^{8 } - 3 i{}^{8} \times i + 3 \div 3 {i}^{10} \times i - 4i {}^{10} - 2$

$4 - 3i + 3 \div 3i {}^{8} \times i {}^{2} \times i - 4 {}^{8} \times i {}^{2}$

7 - 3i/-3i + 4i - 2

7-3i / 1i - 2

7-3i / 1i -2 * 1i +2 / 1i +2

7i + 14 - 3i - 6 /1i*2 - 2*2

4i + 8 / -1 -4

4i + 8 / -5

4i / -5 + 8 / -5 = -4i / 5 - 8i / 5

According to me this is correct.