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◘ Sum of (a + 3b - 4c), (4a - b + 9c) and (-2b + 3c - a) :-
a + 3b - 4c + (4a - b + 9c) + (-2b + 3c - a)
= a + 3b - 4c + 4a - b + 9c - 2b + 3c - a
= a + 4a - a + 3b - b - 2b - 4c + 9c + 3c
= 4a + 0 + 8c
= 4a + 8c
◘ Subtracting (2a - 3b + 4c) from the sum :-
4a + 8c - (2a - 3b + 4c)
= 4a + 8c - 2a + 3b - 4c
= 4a - 2a + 8c - 4c + 3b
= 2a + 4c + 3b
Thus, the final answer is 2a + 4c + 3b.
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