Make the result 100 by taking all the digits 1,2,3,4,5,6,7,8 and 9 only once without
changing their sequence and using + , – or X signs
Answers
Answer:
78+9+6+5+4−3+2−1=100
Step-by-step explanation:
The strategy I would use is the following:
Goal is to get 100 as sum. Among the digits 123456789, pick and choose the sum close to 100, such as 89. Therefore I would attempt to get a value of 11 from 1234567 using different combinations.
When you start working on a smaller sum now (sort of like divide and conquer), you may get the desired result. (Of course there is no specific algorithm).
In order to get 11, I have
(1×23)−4+5−6−7=11
(1−2+3−4+5)×6−7=11
123−45−67=11
Therefore
(1×23)−4+5−6−7+89=100
(1−2+3−4+5)×6−7+89=100
123−45−67+89=100
Adding more to it: If we look at 78+9=87 and instead of 89, we seek the remaining 13 to be derived from 123456, and one way to get that is
6+5+4−3+2−1=13
Therefore
78+9+6+5+4−3+2−1=100
Answer:
123-45-67+89
Step-by-step explanation:
123--45--67+89