Question

Make the subject of the formula:

Answer 1

EXPLANATION.

⇒ y = 5x + 5b/3x - 3a.

As we know that,

Cross multiply both the equation, we get.

⇒ y(3x - 3a) = 5x + 5b.

⇒ 3xy - 3ay = 5x + 5b.

⇒ 3xy - 3ay - 5x - 5b = 0.

⇒ 3xy - 5x - 3ay - 5b = 0.

⇒ x(3y - 5) = 3ay + 5b.

⇒ x = (3ay + 5b)/(3y - 5).

                                                                                                                   

MORE INFORMATION.

Nature of the roots of the quadratic expression.

(1) = Real and unequal, if b² - 4ac > 0.

(2) = Rational and different, if b² - 4ac is a perfect square.

(3) = Real and equal, if b² - 4ac = 0.

(4) = If D < 0 Roots are imaginary and unequal Or complex conjugate.

Answer 2

Given:

y = 5x + 5b/3x - 3a

Now use cross multiplication:

→ y(3x - 3a) = 5x + 5b

→ 3xy - 3ay = 5x + 5b

→ 3xy - 3ay - 5x -5b = 0

→ 3xy - 5x - 3ay - 5b = 0

→ x(3y 5) = 3ay + 5b

→ x = (3ay + 5b)/(3y - 5)

Final answer:

x = (3ay + 5b)/(3y - 5)