Question

make this equation in standard form of quadratic equation ​

Answer 1

Answer:

13x^2 - 41x - 120 =0

Step-by-step explanation:

LHS

Taking Lcm as x(x+3) ,

$\frac{x+3+x}{x(x+3)}$

Now ,

=> 2x+3/x^2+3x =13/40

Cross Multiply,

80x+120 = 13x^2+39x

-13x^2 + 41x + 120 = 0

13x^2 - 41x - 120 =0