Question

make this problem with the whole process system on copy then capture photo of the process and send it FIND THE VALUE

Answer 1

answer is 3
i hope u understand

Answer 2

Hello............^_^

Here is your answer ....

$find \: \: the \: \: value \: \: of \: \frac{ {27}^{ \frac{ - 2}{3} } \times {81}^{ \frac{5}{4} } }{ ({ \frac{1}{3}) }^{ - 3} } \\ \\ \\ factorise \: 27 \: \\ 27 = 3 \times 3 \times 3 \\ 27 = {3}^{3} \\ \\ factorise \: 81 \\ 81 = 3 \times 3 \times 3 \times 3 \\ 81 = {3}^{4} \\ \\ ({3)}^{ - 3} = \frac{1}{ {(3)}^{3} } \\ \\ so \: \: ({ \frac{1}{3} )}^{ - 3} \: \: = {(3)}^{3} \\ \\ \\ = > \frac{ {( {3}^{3} )}^{ \frac{ - 2}{3} } \times { ({3}^{4}) }^{ \frac{5}{4} } }{ ({3})^{3} } \\ \\ \\ = > \frac{ {(3)}^{3 \times \frac{ - 2}{3} } \times {(3)}^{4 \times \frac{5}{4} } }{ {(3)}^{3} } \\ \\ \\ = > \frac{ {(3)}^{ - 2} \times {(3)}^{5} }{ {(3)}^{3} } \\ \\ \\ = > \frac{ {(3)}^{ - 2 + 5} }{ {(3)}^{3} } \\ \\ \\ = > \frac{ {(3)}^{5 - 2} }{ {(3)}^{3} } \\ \\ \\ = > \frac{ {(3)}^{3} }{ {(3)}^{3} } \\ \\ \\ = > {(3)}^{3 - 3} \\ \\ \\ = > {(3)}^{0} = 1$


so it's value is 1



Hope it helps...........^_^