Question

Mala and latha each had a number of bangles. Mala said tc::i latha "if you give me 4 of your bangles, my num]jer will be thrice yours". Latha replied "if you give me 36, my number will be thrice yours". What is the total bangles together with them?

Answer 1

Answer:

$L + M = \frac{4M + 64-560}{3}$

Step-by-step explanation:

Since, Mala and latha each had a number of bangles. Mala said to latha "if you give me 4 of your bangles, my number will be thrice yours". Latha replied "if you give me 36, my number will be thrice yours", our aim is to know what is the total bangles together with them?

Let M be the initial number of bangles of Mala and L be the initial number o bangles of Latha, then:

M + 4 = 3(L - 4)

=> L = (M + 16) / 3

M + 36 = 3(L - 36)

=> M = 3L - 144

Since they should be the same we have:

$L + M = \frac{M+16}{3} + 3L -144\\=4L - \frac{560}{3}\\=\frac{4M + 64-560}{3}$

Hence, we have that $L + M = \frac{4M + 64-560}{3}$

Answer 2

Answer:

The  total bangles together with them =  80

Step-by-step explanation:

Let total number of bangles of Mala = x

Let bangles of Latha = y

Case I -  Mala said to Latha if you give me 4 of your bangles , my number be thrice yours .

So, when we make equation  of this -

=>  x + 4  =3(y - 4)

=> x + 4 = 3y - 12

=>  x - 3y = - 16                                   .................(1)

Case2 - Latha replied if you give me 36, my number will be thrice yours .

So, when we make equation  of this -

=> y + 36 = 3(x - 36)

=> y + 36 = 3x - 108

=> 3x - y = 144                                     ....................(2)

Solving equations (1) and (2) by elimination method

So,  3x - 9y = - 48

and 3x - y =   144

=>  -8y = - 192

=>  y  =  24

=>  x =  -16 + 3*24

        =  56

Thus, total bangles together with them = Bangles of Mala + Bangles of Latha

= x + y

= 24 + 56

=  80

So, total bangles together with them = 80