Question

mali start chesava





1. An insect is crawling inside a hemispherical bowl of radius r. If the coefficient of friction between the bowl and insect is u find the maximum height to which the insect can crawl.



don't spam ❌​

Answer 1

Answer:

An insect is crawling up a hemispherical bowl whose radius =R

If the coefficient of fraction =

3

1

Then the insect will be able to go up to height

h=?

10

3

=0.95

N=wcosθ

f=wsinθ

N

f

=tanθ=

3

1

⇒tanθ=18.43

∴cosθ=

(1/3)

2

+1

1

r

r−h

=

(1/3)

2

+1

1

=0.986

h=r(1−

μ

2

+1

1

)

=r(1−0.9486)

h=r(0.9486)

wherer=Rthen,

h=R(0.9486)

Explanation:

pls inbox me

pls pls

Answer 2

hope it may help you

please mark me as brainliest