Question

Mamimum n.o of electron present in nickel for which m=1 is

Answer 1

Answer:

Conventionally, the location of an electron is written in the following way,

n, l, ml, msn, l, ml, ms

nn represents the principal quantum number,

ll represents the azimuthal quantum number,

mlml represents the magnetic quantum number

msms represents the spin quantum number.

The absolute value of the magnetic quantum number must be less than or equal to that of the azimuthal quantum number. This means that the azimuthal quantum number must be greater than or equal to 1 (according to your question). Because the azimuthal quantum number must be less than that of the principal quantum number, the principal quantum number must be greater than or equal to 2.

Remember that the azimuthal quantum number corresponds to the subshell.

0 - ss subshell, 1 - pp subshell, 2 - dd subshell, 3 - ff subshell,

The ground state electron configuration of nickel is 1s2 2s2 2p6 3s2 3p6 4s2 3d81s2 2s2 2p6 3s2 3p6 4s2 3d8

Now, time to find electrons in orbitals that fit our requirements. First, n≥2n≥2, this gives us:

2s 2p 3s 3p 4s 3d2s 2p 3s 3p 4s 3d

Second, l≥1l≥1, this gives us:

2p 3p 3d2p 3p 3d

Because we want the magnetic quantum number to be only 1 or -1, there are two possibilities for orbitals each that fulfill the requirements.

This gives us 2 + 2 + 2 or

6 possibilities.

Explanation:

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