Man a of mass 60kg pushes other man b of mass 75 kg due to which man b starts moving with acceleration 3 m/s.calculate acceleration of man a at that instant
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mB=75kg mA=60kg
vB=3m/s vB=?
mAvA=mBvB (conservation of momentum)
60*vB=75*3
vB=3.75m/s
vB=3m/s vB=?
mAvA=mBvB (conservation of momentum)
60*vB=75*3
vB=3.75m/s
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