Physics, asked by selvarajkollarpatti, 18 days ago

man decided to cover a distance of 6km in 84 minutes . he decided to cover tow thirds of the distance at 4km / hr and the remaining at some different speed . find the speed after the two third distance has been covered​

Answers

Answered by mrnothing056
0

Time taken to cover a distance of 6 km = 84 minutes

Two thirds of the 6 km was covered at 4 km/hr

Formula used:

Time = Distance/Speed

Calculation:

Two thirds of 6 km = 6x(2/3) = 4 km

Speed for 4 km distance cover = 4 km/hr

So, Time = 4 km/4 km/hr = 1 hr = 60 minutes

⇒ Time left = 84 - 60 = 24 minutes = 24/60 = 0.4 hours

Remaining distance = 6 - 4 = 2 km

⇒ Speed required for remaining 2 km = D/T = 2 km/0.4 hr = 5 km/hr

∴ Speed after the two third distance has been covered is 5 km/hr

khatam! the end !

Answered by mahiichy01
0

Given : Time taken to cover a distance of 6 km =

84 minutes

He covered Two third of the 6 km at 4

km/hr

Formula :

Time = Distance/Speed

Solution:

Two thirds of 6 km = 6x(2/3) = 4 km

Speed for 4 km distance cover = 4 km/hr

So, Time = 4 km/4 km/hr = 1 hr = 60 minutes

  • → Time left = 84 - 60 = 24 minutes =

24/60 = 0.4 hours

Distance Left = 6 - 4 = 2 km

  • → Speed required for left distance of 2 km = D/T = 2 km/0.4 hr = 5 km/hr

:: Speed after the two third distance has been covered is 5 km/hr

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