Question

man driven a bike with speed of 36km/ applied brake due to hump on road. h.He ) Find acceleration if it covers the distance of 10km before stop?​

Answer 1

Answer:

10m

Explanation:

Equations are to be applied is "v = u - a×t " and "S = u×t - (1/2)×a×t2 "

v is final velocity, u initial velocity, a is retardation, S is distance travelled and t is time.

initial velocity = 36 km/h ×(5/18) = 10 m/s

(1) retardation :- 0 = 10-a×2 , solving for a we get retardation a = 5 m/s2

(2) distance :- S = 10×2 -(1/2)×5×4 = 10 m

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