Question

man earns rs. 600 per month more than his wife. one-tenth of the man’s salary and one-sixth of the wife’s salary amount to rs. 1500, which is saved every month. find their incomes.

Answer 1

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Answer 2

Answer:

Monthly income of wife = Rs. 5400

And, Monthly income of man = 5400+600 = Rs. 6000

Explanation:

Given,

A man earns ₹600.per month more than his wife one tenth of the men salary and one -sixth of the wife salary amount to ₹1500.

To find: Income of man and wife saved every month.

Concept Involved: Through the use of question's language we will form equations and solving those equations will get us the resultant.

Solution:

Let the monthly income of wife be x.

then, monthly income of man will be (x + 600)

Now, According to question,

1 (x + 600) / 10 + 1(x) / 6 = 1500

or, [ 3(x+600) + 5x] / 30 = 1500

or,  8x + 1800 = 1500 * 30

or, 8x = 45000 - 1800

or, x = 43200/8

or, x = 5400.

Therefore, Monthly income of wife = Rs. 5400

And, Monthly income of man = 5400+600 = Rs. 6000