man is pulling the string with 400N. want is the normal force between man and the platform. also find acceleration.
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Answer:
N=600N
a=10m/s²
Explanation:
observing From it from the ground,
I have taken g=10m/s²...
suppose that both the system move in upward direction with acceleration a m/s²...
from 1st fbd
T+N-60g=60a...(i)
from 2nd fbd
T-(N+15g)=15a....(ii)
From 3rd fbd
T=F=600N
adding (i) and (ii),we get
2T-45g=75a
=>1200-450=75a
=>a=750/75 =10m/s²
hence,N=60a+60g-T
=>N=600+600-600=600N
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