Physics, asked by Anonymous, 8 months ago

man is pulling the string with 400N. want is the normal force between man and the platform. also find acceleration.

ANYONE TO SOLVE?? ​

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Answers

Answered by Anonymous
1

Answer:

N=600N

a=10m/s²

Explanation:

observing From it from the ground,

I have taken g=10m/s²...

suppose that both the system move in upward direction with acceleration a m/s²...

from 1st fbd

T+N-60g=60a...(i)

from 2nd fbd

T-(N+15g)=15a....(ii)

From 3rd fbd

T=F=600N

adding (i) and (ii),we get

2T-45g=75a

=>1200-450=75a

=>a=750/75 =10m/s²

hence,N=60a+60g-T

=>N=600+600-600=600N

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Answered by Anonymous
2

Answer:

Hey this is Shivani. We can definitely be friends ❣❣

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